Monday, August 18, 2008
Personal Message from Mr.Nava.S
Have a great holiday and have fun studying. Cheers.
Mr.Nava.S
Thursday, August 7, 2008
Discussion 1 - Refraction of light
Diagram 1
Diagram 2
Discussion
All the questions is about Snell’s Law
Remember an important point when applying the formulae
n = sin i/ sinr
sin i = the value must be taken from air even if the ray is coming it coming from a medium
sin r = value from mediumCan you tell which is the incident angle, i and the refraction angle, r when light travels from glass to air ?
refering to diagram 1
Most of us think that the a is the incident angle, i ….its not wrong to think like that but if we apply the a value as sin i then ..lets see what’s happens to the index value(n)
n=sin 30/sin 40 =0.78
its less than 1… vice versa…if I let the ray in as in diagram 2 then it will go back the same way(from air to glass with same angle) . Agree ?
so in this case…b will be the incident angle, i …so
n = sin 40/sin 30 =1.29
so which value is right ?
index value should always be more than 1 for a medium
in this case the value 1.5 is the correct one
so to avoid confusion between incident angle and refraction angle….no worries
from this ,
n = sin i(air)/sin r(medium) ……no matter where the ray coming from….
Answer : Question 23&24
Question 23
i. a) r = 19◦
b) n = 1.54 …………no unit for refractive index
ii. n = 1.40
Question 24
a) c = 24.6◦
b) n = 1/sin c = 2.4

